docs: Fix typos in docs
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@ -350,7 +350,7 @@ then `φ * 𝓝(φ₀φ₁…φₙ)` is equal to
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`𝓝(φφ₀φ₁…φₙ) + ∑ i, (𝓢(φ,φ₀φ₁…φᵢ₋₁) • [anPart φ, φᵢ]ₛ) * 𝓝(φ₀…φᵢ₋₁φᵢ₊₁…φₙ)`.
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The proof of ultimately goes as follows:
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The proof ultimately goes as follows:
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- `ofFieldOp_eq_crPart_add_anPart` is used to split `φ` into its creation and annihilation parts.
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- The following relation is then used
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